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Paha777 [63]
2 years ago
9

Can u guys please help a poor soul 1/root 5 - root 3

Mathematics
2 answers:
Stolb23 [73]2 years ago
3 0

Answer:

1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer

Step-by-step explanation:

NISA [10]2 years ago
3 0

hope it really helps......!!!!!!

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I’m really confused please help
sveticcg [70]

Answer: probly d

Step-by-step explanation:

a ,b ,and c are subtracting makeing it hard top get something that was not in the problem

6 0
2 years ago
At a fish market, a pound of salmon costs $12 and a pound of shrimp costs $18. Mrs. Donnelly wants to buy 2 1/3 pounds of salmon
Semmy [17]

Answer:

Yes and she would have $2 left over because all the food costs $91.

Step-by-step explanation:

We should set up an equation so that everything makes sense. A calculator would be wise for this problem, but I am going to lay it out anyhow.

We should convert the mixed numbers to improper fractions to not be confused. 3 1/2 becomes 7/2 or 3.5 and 2 1/3 becomes 7/3.

From your wording, we can assume that the money Mrs. Donnelly has is either greater than or equal to $93.

Thus, we have 12*(7/3) + 18*(7/3) is equal to or greater than 93 (this is an inequality).

The math shows that the food costed 91 and so she only has $2 left.

7 0
3 years ago
Katie has 4 times as many songs on her music player as Lou. Tiffany has 6 times as many songs on her music player as Lou. Altoge
Dmitry_Shevchenko [17]

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7 0
3 years ago
9 please help with 9 <br><br> 10 what is P
LenaWriter [7]

Answer:

9.

The probabilities are the same

10.

1/3

Step-by-step explanation:

9.

Assuming the coin is fair;

The probability of getting heads in a single toss is, P(H) = 1/2

The probability of getting tails in a single toss is, P(T) = 1/2

Now, P(H,H,H) is the probability of obtaining 3 heads in the e tosses. Since each toss is independent of the others,;

P(H,H,H) = P(H)*P(H)*P(H)

              = 1/2 * 1/2 * 1/2 = 1/8

On the other hand, P(H,T,H) is the probability of obtaining a head followed by a tail followed by a final head. Using the independence property;

P(H,T,H) = P(H)*P(T)*P(H)

              = 1/2 * 1/2 * 1/2 = 1/8

Therefore, P(H,H,H) = P(H,T,H)

10.

We are informed that a coin is tossed and a number cube is rolled. We are to determine the following probability;

P(heads, a number less than 5)

Assuming the coin is fair;

The probability of getting heads in a single toss is, P(H) = 1/2

Assuming the number cube is fair as well, the probability of rolling a number less than 5 is;

4/6 = 2/3

This is because there are 4 numbers less than 5, (1, 2, 3, 4) while the cube has 6 sides.

P(heads, a number less than 5), the events presented here are independent since the outcome from tossing the coin does not in any way determine the outcome from rolling the number cube. Therefore,;

P(heads, a number less than 5) = P(heads)*P(a number less than 5)

                                                    = 1/2 * 2/3 = 1/3

3 0
3 years ago
PLSSS<br><br> C= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B12%5E%7B3%7D%20.%206%5E%7B5%7D%20%7D%7B9%5E%7B4%7D%20.%202%5E%7B10%
Rudiy27

Answer:

2

Step-by-step explanation:

The trick here is to reduce each of the bases to lowest form first

12 = 3.4 = 3 .2.2  = 3.2^{2}\\12^{3}  = (3.2^{2} )^{3} = 3^{3}2^{6}  \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator }  =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2  

7 0
2 years ago
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