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Paha777 [63]
2 years ago
9

Can u guys please help a poor soul 1/root 5 - root 3

Mathematics
2 answers:
Stolb23 [73]2 years ago
3 0

Answer:

1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer

Step-by-step explanation:

NISA [10]2 years ago
3 0

hope it really helps......!!!!!!

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3 years ago
If a toy rocket is launched vertically upward from the ground level with an initial velocity of 128 feet per second, then its he
natta225 [31]

Answer:

The maximum height of the rocket is 256 feet

Step-by-step explanation:

The vertex form of the quadratic function f(x) = ax² + bx + c is

f(x) = a(x - h)² + k, where

  • (h, k) is the vertex point
  • h = \frac{-b}{2a} and k = f(h)
  • (h, k) is a minimum point if a > 0 and a maximum point if a < 0

Let us use these rules to solve the question

∵ h(t) = -16t² + 128t

→ Compare it by the form of the quadratic function above

∴ a = -16 and b = 128

∵ a < 0

∴ The vertex (h, k) is a maximum point

∴ The maximum height of the rocket is the value of k

→ Use the rule of h above to find it

∵ h = \frac{-128}{2(-16)} = \frac{-128}{-32}

∴ h = 4

→ Substitute x in the equation by the value of h to find k

∵ k = h(h)

∴ k = -16(4)² + 128(4)

∴ k = -256 + 512

∴ K = 256

∴ The maximum height of the rocket is 256 feet

4 0
3 years ago
I don’t know how to do this for nothing
Vadim26 [7]

Answer:

ok

Step-by-step explanation:

4 0
2 years ago
Select the correct answer.
Elena L [17]

Answer:

b because first u need to remove the parentheses then u disturbe

8 0
3 years ago
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