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larisa [96]
3 years ago
9

7 and 5 (fractions) x = 7 and 15 (fractions) please just give me the full equation to put with the answer

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

\frac{7}{5} * \frac{1}{3} = \frac{7}{15}



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Please help me answer this question. First to answer will be marked braineist. NO WORK NESSACARY. Thank you ☺️
m_a_m_a [10]

Lets check the first point (0,6)


3*0+4=4  no good

0+6 =6  good

0^2+6 =6 good

6 * (7/6) ^0 =6  good


Lets check the second point (1,7)

3*1+4=  we don't care since it didn't work for (0,6)

1+6 =7

1^2+6 =7

6 * (7/6) ^1 =7


Lets check the third point (2,10)


3x+4=  we still don't care

2+6 = 8 no good

2^2+6 =10  good

6 * (7/6) ^2 =6 * 49/36 =49/6  no good


f(x) = x^2 +6


7 0
3 years ago
Use the distributive property to expand: x^-3 y^0(x^2-3x^5 y^4)
Soloha48 [4]

{x}^{ - 3}  {y}^{0} ( {x}^{2}  - 3 {x}^{5}  {y}^{4} ) \\  =  {x}^{ - 3}  (1) ( {x}^{2}  - 3 {x}^{5}  {y}^{4} ) \\  =  {x}^{ - 1}  - 3 {x}^{2}  {y}^{4}

4 0
4 years ago
Determine whether the two triangles are similar. If they are similar, write the singularity statement​
Keith_Richards [23]

Answer:

no

Step-by-step explanation:

6 0
4 years ago
(I WILL RATE BRAINIEST)
Umnica [9.8K]

Answer:

(a)

Shortest Side of the trapezoid =6 yds

Longest Side =8 yds

(b)42 Square Yards

Step-by-step explanation:

<u>Part A</u>

In the Trapezoid, Width =6 yd

Since the shortest side of the playground and its width have the same dimension, then:

  • Shortest Side of the trapezoid =6 yd
  • Longest Side =6+1+1=8 yd

<u>Part B</u>

Area of the Playground

In the trapezoid

a=6 yd, b=8 yd, h=Width=6 yd

Area of a trapezoid=\frac{1}{2}(a+b)h<u />

<u />Therefore: Area=\frac{1}{2}(6+8)*6\\=14*3\\=42$ Square Yards<u />

7 0
3 years ago
I NEED HELP PLEASE ! :(
denis-greek [22]

Answer:

4

Step-by-step explanation

because 256 is root of  4 raised to 4

so 4 root 4 is to 4 which is = to 4

hope it helped u i am new on brainly so counldnt write properly

if it helped u plzzz mark as brainliest

3 0
3 years ago
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