Answer:
This is because modulus number will be always positive
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Could i have the answer to this question please?
1 answer:
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Answer:
A, C, D and K
Step-by-step explanation:
Inequalities:
y ≤ −2x + 10 and y >1/2x-2
<u>Finding zeros for the first inequality:</u>
- x=0 ⇒ y= 10, point (0, 10)
- y=0 ⇒ x= 5, point (5, 0)
- Locating these 2 points and connecting to get the first line.
Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.
<u>Finding zeros for the second inequality:</u>
- x=0 ⇒ y= -2, point (0, -2)
- y= 0 ⇒ x= 4, point (4, 0)
- Locating these points and connecting to get the second line.
Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.
Now we have the space of intersection of the above inequalities.
So the points in same section are the solution.
They are:
- Points A, C, D and K
See attached for explanation
