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PIT_PIT [208]
3 years ago
13

Could i have the answer to this question please?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

a) I don't know sorry

b) i think 2,25km but i'm not sure

Step-by-step explanation:

1:25 000 cm

1:25 00 dm

<u>1:250 m</u>

1:0,025 km

9.250=2250

2,25

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Step-by-step explanation:

The sum of all angles in a triangle is always 180.

So we can set up an equation

3/2x+1/2x+x= 180

3/2+1/2x+2/2x=180

3x+1x+2x=360

6x=360

x=60

4 0
3 years ago
PLEASE HELP!!! <br> EXPLANATIONS ARE APPRECIATED
Vlada [557]

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Read 2 more answers
Set of data with 350,000 numbers is normally
Rudiy27

Step-by-step explanation:

given a normal distribution with the given parameters the probability (= the % of the area of the distribution curve) for a number to be between 203 and 1803 is

0.9987

so, 99.87% of all numbers are expected to be in that range.

for 350,000 numbers that means

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7 0
2 years ago
Which equation has infinite solutions?
AnnyKZ [126]

The equation that has an infinite number of solutions is 2x + 3 = \frac{1}{2}(4x + 2) + 2

<h3>How to determine the equation?</h3>

An equation that has an infinite number of solutions would be in the form

a = a

This means that both sides of the equation would be the same

Start by simplifying the options

3(x – 1) = x + 2(x + 1) + 1

3x - 3 = x + 3x + 2 + 1

3x - 3 = 4x + 3

Evaluate

x = 6 ----- one solution

x – 4(x + 1) = –3(x + 1) + 1

x - 4x - 4 = -3x - 3 + 1

-3x - 4 = -3x - 2

-4 = -2 ---- no solution

2x + 3 = \frac{1}{2}(4x + 2) + 2

2x + 3 = 2x + 1 + 2

2x + 3 = 2x + 3

Subtract 2x

3 = 3 ---- infinite solution

Hence, the equation that has an infinite number of solutions is 2x + 3 = \frac{1}{2}(4x + 2) + 2

Read more about equations at:

brainly.com/question/15349799

#SPJ1

<u>Complete question</u>

Which equation has infinite solutions?

3(x – 1) = x + 2(x + 1) + 1

x – 4(x + 1) = –3(x + 1) + 1

2x + 3 = \frac{1}{2}(4x + 2) + 2

\frac 13(6x - 3) = 3(x + 1) - x - 2

5 0
2 years ago
How do I find a unit rate of 17.86
Reil [10]
To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate. So in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate. <— that’s your answer! :)
8 0
4 years ago
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