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Rudik [331]
4 years ago
11

the temperature is 50, The temperature will decrease by 4 each hour. Let H be the number of hours. Write an inequality for this

problem
Mathematics
1 answer:
natita [175]4 years ago
5 0
Answer:
50 - 4H = x

the starting temp is 50 and H represents the number of hours multiplied by 4. you subtract that product from 50 and you can find x
You might be interested in
What is the approximate solution to the equation 3^t=29 ? a) 0.3263 b)3.0650 c) 3.3672 d) 9.6667
Vinvika [58]

Answer:

b

Step-by-step explanation:

using the law of logarithms

• log x^{n} = nlogx

given 3^{t} = 29 ( take log of both sides, that is base 10 )

log 3^{t} = log 29, hence

tlog 3 = log29 (divide both sides by log 3 )

t = \frac{log29}{log3} ≈ 3.0650 → b



7 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
Simplify completely and find the restrictions on the variable.​
MatroZZZ [7]

Answer:

\displaystyle \frac{x + 2}{x + 9}, \ x \neq  -9, \ 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Discontinuities
  • Domain Restrictions

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{x^2 - 10x - 24}{x^2 - 3x - 108}<u />

<u />

<u>Step 2: Simplify</u>

  1. [Fraction] Factor numerator:                                                                           \displaystyle \frac{(x - 12)(x + 2)}{x^2 - 3x - 108}
  2. [Fraction] Factor denominator:                                                                       \displaystyle \frac{(x - 12)(x + 2)}{(x - 12)(x + 9)}
  3. [Fraction] Divide:                                                                                              \displaystyle \frac{x + 2}{x + 9}

We know that <em>x</em> cannot equal -9 because we would get a divide by 0 (undefined) error. We also know that <em>x</em> cannot equal 12 because it was canceled out when simplifying.

7 0
3 years ago
The milk jug is 7/8 ​ full. After pouring some out for dinner, the milk jug is 4/7 ​ full. What fraction of the milk jug did you
xeze [42]
17/56
So to make sure that you are subtracting right, you make the denominators the same. So the denominator is 56 because it is a common number for 7 and eight. And then whatever you do to the bottom you got to do to top so time seven by eight and 4 which is 49 and 24 so 49-24 is 17/56 so the answer would be this because you can’t simplify the answer down.
8 0
3 years ago
Read 2 more answers
161/4=<br> ........................<br> 1/2<br> 2<br> 4
tia_tia [17]
161/4=40.25 so none of those choices match
5 0
4 years ago
Read 2 more answers
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