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2 years ago

Convert the unit. of length

Mathematics

1 answer:

Sergio [31]2 years ago

4 0

Answer:

50688

Step-by-step explanation:

thats all i got sorry if thats wrong but i hope this helps.

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vaieri [72.5K]

891 were sold
.55x1800= 990
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990-99= 891

5 0

3 years ago

Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1

lana [24]

We assume that the function is as follows:

$f^{-1_{}}(2)=?$

Then, we have that:

$f^{-1}(x)=\frac{1}{f(x)}$

Thus, if we have that:

$f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}$

Therefore, the value for the function is f^-1(2) = -1/2 or

$f^{-1}(2)=-\frac{1}{2}$

8 0

1 year ago

Please help I am really confused with this

mario62 [17]

The answer should be A. 4 Meters

5 0

2 years ago

1. Here is a rule to make a list of numbers: Each number is the sum of the

boyakko [2]

Answer:

what the rest of the problem?

Step-by-step explanation:

8 0

3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

Convert the unit. of length​

Convert the unit. of length