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postnew [5]
2 years ago
6

Convert the unit. of length​

Mathematics
1 answer:
Sergio [31]2 years ago
4 0

Answer:

<u>50688</u>

Step-by-step explanation:

<em>thats all i got sorry if thats wrong but i hope this helps.</em>

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990-99= 891
5 0
3 years ago
Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1
lana [24]

We assume that the function is as follows:

f^{-1_{}}(2)=?

Then, we have that:

f^{-1}(x)=\frac{1}{f(x)}

Thus, if we have that:

f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}

Therefore, the value for the function is f^-1(2) = -1/2 or

f^{-1}(2)=-\frac{1}{2}

8 0
1 year ago
Please help I am really confused with this​
mario62 [17]

The answer should be A. 4 Meters

5 0
2 years ago
1. Here is a rule to make a list of numbers: Each number is the sum of the
boyakko [2]

Answer:

what the rest of the problem?

Step-by-step explanation:

8 0
3 years ago
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
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