Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
That would be -0.041
-0.125/3 = -0.041666666
Answer:
No solutions
Step-by-step explanation:
i did this via substitution so i hope it isn't a problem
3x+y=4
6x+2y=−4
Step: Solve 3x+y=4for y:
3x+y+−3x=4+−3x(Add -3x to both sides)
y=−3x+4
Step: Substitute−3x+4foryin6x+2y=−4:
6x+2y=−4
6x+2(−3x+4)=−4
8=−4(Simplify both sides of the equation)
8+−8=−4+−8(Add -8 to both sides)
0=−12
so there are no solutions
hope this helps!!
36 × 0.07 = $2.52 sales tax
Answer: 23in squared
Step-by-step explanation:
9 plus 4 plus 10
