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2 years ago

6

Sue had a circular picture that she wanted to frame. If the picture's frame diameter was

1 answer:

sesenic [268]2 years ago

7 0

Sue had 7.5 inches framing

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2 years ago

[20 pts] evaluate the logarithm log(6)1/36, show work pls!

Delvig [45]

Answer:

$\large\boxed{\log_6\dfrac{1}{36}=-2}$

Step-by-step explanation:

$\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2$

$\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}$

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2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −6y2 − 9y = −1

Tomtit [17]

$-6y^2 - 9y = -1$

$y= \dfrac{-9+ \sqrt{9^2-4*-6} }{2*6}, \dfrac{-9-\sqrt{9^2-4*-6}}{2*6}$

$y= \dfrac{-9+ \sqrt{105} }{12}, \dfrac{-9- \sqrt{105} }{12}$

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3 years ago