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Mashcka [7]
3 years ago
15

If Addison types at a constant rate of 2 pages per hour, how many hours will it take to type a paper that is 5 pages long?

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

2.5 hours

Step-by-step explanation:

Find unit rate so 1 page per 30 mins. 30 x 5 = 150 minutes. Since it asks for hours, 150/60= 2 hours and 30 minutes or 2.5 hours

Romashka [77]3 years ago
6 0

Answer:

The answer is B

Step-by-step explanation:When you do 2 pages an hour, 2 hours is 4 pages, but you dont need an extra whole hour, instead just add a half which is why the answer is 2.5 hours.

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A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as
abruzzese [7]

Answer:

88

Step-by-step explanation:

5GP= BP

2BNP= GNP

BP+BNP=333

GP+GNP=225

BNP= 333-BP

BNP= 333-5GP

GP= 225-GNP

GP= 225-2BNP

BNP=333-5(225-2BNP)

BNP=333-1125+10BNP

-9BNP=-792

BNP=88

Hope it helps :)

Mark Brainliest if possible.

7 0
4 years ago
Read 2 more answers
If f(x) = |x| + 9 and g(x) = –6, which describes the range of (f + g)(x)?
Leokris [45]
Just want points byeeee hope u fail jkjkjk
3 0
3 years ago
4. Simplify the expression.<br> -3 (b-7)
Arturiano [62]

Answer:

The answer is -3b+21

5 0
3 years ago
in a city school of 1,200 students, 40% of the students are on the honor roll, 60% have a part-time job, and 22% are on the hono
Alexus [3.1K]
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job

We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)

We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability

P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate

Convert this to a percentage to get roughly 36.67% and this rounds to 37%

Final Answer: 37%

4 0
3 years ago
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t
rosijanka [135]

Answer:

Height = 12cm

Radius = 6cm

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

V = 432\pi

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

V = \pi r^2h\\

Substitute 432π for V

432\pi = \pi r^2h

Divide through by π

432 = r^2h

Make h the subject:

h = \frac{432}{r^2}

Surface Area (A) of a cylinder is calculated as thus:

A=2\pi rh+2\pi r^2

Substitute \frac{432}{r^2} for h in A=2\pi rh+2\pi r^2

A=2\pi r(\frac{432}{r^2})+2\pi r^2

A=2\pi (\frac{432}{r})+2\pi r^2

Factorize:

A=2\pi (\frac{432}{r} + r^2)

To minimize, we have to differentiate both sides and set A' = 0

A'=2\pi (-\frac{432}{r^2} + 2r)

Set A' = 0

0=2\pi (-\frac{432}{r^2} + 2r)

Divide through by 2\pi

0= -\frac{432}{r^2} + 2r

\frac{432}{r^2} = 2r

Cross Multiply

2r * r^2 = 432

2r^3 = 432

Divide through by 2

r^3 = 216

Take cube roots of both sides

r = \sqrt[3]{216}

r = 6

Recall that:

h = \frac{432}{r^2}

h = \frac{432}{6^2}

h = \frac{432}{36}

h = 12

Hence, the dimension that requires the least amount of material is when

Height = 12cm

Radius = 6cm

3 0
3 years ago
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