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3 years ago

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

Mathematics

1 answer:

lakkis [162]3 years ago

6 0

Answer:

m = n = 20

Step-by-step explanation:

Here, we want to find the missing side lengths

For a 45-45 triangle, the lengths have a side ratio of;

1:1: √2

We should understand that the triangle is isosceles ( opposite and adjacent are equal)

So n = m

So what we just need to do here is divide 20 √2 by √2

Mathematically, that would be;

20 √2/√2 = 20

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Based on data from a college, scores on a certain test are normally distributed with a mean of 1530 and a standard deviation of

harkovskaia [24]

Answer:

0.73% of the scores are greater than 2317.

14.46% of the scores are less than 1190.

38.23% of the scores are between 1351 and 1673.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1530, \sigma = 322$

Find the percentage of scores greater than 2317.

This is 1 subtracted by the pvalue of Z when X = 2317. So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2317 - 1530}{322}$

$Z = 2.44$

$Z = 2.44$ has a pvalue of 0.9927.

So 1-0.9927 = 0.0073 = 0.73% of the scores are greater than 2317.

Find the percentage of scores less than 1190.

This is the pvalue of Z when X = 1190. So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1190 - 1530}{322}$

$Z = -1.06$

$Z = -1.06$ has a pvalue of 0.1446.

So 14.46% of the scores are less than 1190.

Find the percentage of scores between 1351 and 1673.

This is the pvalue of Z when X = 1673 subtracted by the pvalue of Z when X = 1351. So

X = 1673

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1673- 1530}{322}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

X = 1351

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1351- 1530}{322}$

$Z = -0.56$

$Z = -0.56$ has a pvalue of 0.2877

So 0.67-0.2877 = 0.3823 = 38.23% of the scores are between 1351 and 1673.

4 0

3 years ago

Verify cos(180+x)=-cosx<br> Please note the 180 is in degrees.

inna [77]

The angle sum identity for cosine says that

$\cos(180^\circ+x)=\cos180^\circ\cos x-\sin180^\circ\sin x=-\cos x$

because $\cos180^\circ=-1$ and $\sin180^\circ=0$ .