Answer:
- 0.3sin6000t A
Explanation:
Voltage, v = 10 cos 6000t V
Capacitance = 5-uF
Current flowing through, i(t)
i(t) = c * d/dt (V)
c = 5-uF = 5 * 10^-6 F
i(t) = (5 * 10^-6) * d/dt(10 cos 6000t)
d/dt(10 cos 6000t) = (10 * 6000) * (-sin 6000t)
Hence,
i(t) = (5*10^-6) * (10*6000) * (-sin 6000t)
i(t) = 5*10^-6 * 6*10^4 * - sin6000t
i(t) = 30 * 10^-2 * - sin6000t
i(t) = 0.3*-sin6000t
i(t) = - 0.3sin6000t Ampere
Answer:
The correct one is (III)
Explanation: Limited and uncertain supply and the increasing requirements for pollution control are raising the cost of using fossil fuels.
This is because fossil fuels emit green house gases that are causing global warming. As a result more awareness have been drawn towards the harmful use of fossil fuels, and international bodies are starting to form regulations on the use of fossil fuels. These above reasons has made fossil fuels though abundant, very expensive to use.
This make the usage of greener sources of energy like solar energy desirable. The only challenge solar is facing is on the area of efficiency, but scientists are constantly researching to make it more efficient.
Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3
= 5 3 2
x_{f} = 45 m
we substitute

v = 15 m / s
Answer:
Mia is correct, but did not show a lot of work.
Explanation:
Mia must explain her answer and give reasoning by using what knowledge she has on the subject.
Answer:
7. Net constant force down the ramp
Explanation:
After the car is released and starts moving up the ramp, the only force that is applied on the car is weight because of the gravity, we were told that the friction force is neglected. the force because of the weight is given by:

where θ is the angle of the ramp.
as you can see those values won't change, so the force remains constant down the ramp.