Ep = mgh = 47.0 J
m = 0.8 kg
g = 9.81 m/s2 (average)
h = Ep / mg = 47 J / 0.8 kg * 9.81 m/s2 = 5.989 m
Answer:
<u>59637.2 N</u> force is required to lift the plane upward.
Explanation:
Mass of the aeroplane (m) = 5320 kg
Acceleration of the plane upward at a rate (a) = 1.40 m/s
"Newton's second law of motion", F - R = ma, where, "force" (F) acting on an object, (R) "resistive force", "mass" (m) of an object and "acceleration" (a).
Force = Resistive force + (mass × acceleration)
Resistive force = mass of an object × acceleration due to gravity. ( we know that acceleration due to gravity is
Resistive force = 5320 × 9.81
Resistive force = 52189.2 N
Force = 52189.2 + (5320kg × 1.40 m/s)
Force = 59637.2 N
At takeoff, <u>59637.2 N</u> force is necessary to accelerate the plane upward at a rate of 1.40 m/s
.
Answer:
98.4 N
Explanation:
Given that the body weighs 800 N on earth.
Thus,
Weight = mass x acceleration due gravity
i.e W = mg
800 = m x 10
m =
= 80 kg
The mass of the body is 80 kg.
To be able to determine its weight on the planet, we have to first calculate the gravitational pull of the planet.
But,
g =
Where: G is the Newton's universal gravitation, M is the mass of the planet and r is the radius of the planet.
g =
=
= 1.2275
g = 1.23 m/
Thus,
Weight of the body on the planet = mg
= 80 x 1.23
= 98.4 N
The weight of the body on the planet is 98.4 N
Answer:
P=1113.35 psi
Explanation:
For tank 1
V₁= 6.25 L
P₁=1759 psi
For tank 2
V₂=6.25 L
P₂=467.7 psi
Lets take final pressure is P
The final volume V= 6.25 + 6.25 L = 12.5 L
P V = V₂P₂+V₁P₁
Now by putting the values
P V = V₂P₂+V₁P₁
P x 12.5 = 6.25 x 467.7+6.25 x 1759
P=1113.35 psi
So the final volume of the system will be 1113.35 psi.
Answer:
Verified that he oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude.
Explanation:
Starting from the first principle for the derivation and to prove that the oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude. The mathematical manipulations was applied, trigonometric identities was also applied.The steps and explanation are shown in the attachment.