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4 years ago

Click any that apply. Examples of heat conduction via radiation include:

Physics

2 answers:

Ahat [919]4 years ago

6 0

Answer:

The sun and a heat lamp.

2 and 4

trapecia [35]4 years ago

3 0

The sun and heat lamp I think I could be wrong

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You want to set up an aquarium and need to determine what size tank to buy. The graph shows tank sizes using a rule that relates

sineoko [7]

connexus unit 8 lesson 1 PRACTICE!

1) B

2) C

3) A

4) C

5) B

6) A

7) D

8) A

9) D

10) A

11) A

12) C

13) D

14) C

15) B

16) B

Hope this helps you guys out!

4 0

3 years ago

Read 2 more answers

Page worth 100 points please help

laila [671]

Answer:

a) the total circle of "initial" is Epot./Eel. and the total circle of "final" is Ekin.

b)intia: 0.5 * 50 * 4^2 = 400 J

final: 0 J = 0.5 * 50 * 0^2

Explanation:

c) in the initial phase the spring is compressed and so has Epot but then the Energie changes to be totally Ekin (in final phase) and so the Epot becomes 0

5 0

3 years ago

Read 2 more answers

I need help with one through six please

dybincka [34]

Answer:

1] 8500000 = 8.5 × 10⁶

2] .000072 = 7.2 × 10⁻⁵

3] 5.3 × 10⁴ = 53000

4] 2.8 × 10⁻³ = 0.0028

5] Velocity = $\frac{distance}{time}$

V = $\frac{50}{10}$

V = 5 m/s

6] Acceleration = $\frac{V1-V2}{time}$

A = $\frac{30-15}{3}$

A = $\frac{15}{3}$

A = 3 m/s²

7 0

2 years ago

You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi

Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

$E_A} =E_{B}$

Spring potential energy =potential energy due to elevation

0.5*k*x²= mg $(h_{B}-h_{A} )$ =mgh

0.5*k*2.3²= 430*9.81*6

k=9568.92 N/m

For safety reason

k"=1.13 *k= 1.13*9568.92

k"=10812.88 N/m

agsin from conservation of energy

$E_A} =E_{C}$

spring potential energy=change in kinetic energy

0.5*k"*x²=0.5*m* $V_{max}^{2}$

10812.88 *2.3²=430* $V_{max}^{2}$

$V_{max}$ =11.53 m/s

5 0

4 years ago

A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I

Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = $\frac{4\times \pi^2\times r^3}{GM}$ where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0

3 years ago