All categories

3 years ago

27 to the power of 3x=81

Mathematics

1 answer:

hoa [83]3 years ago

8 0

Answer:

x=4/9

Step-by-step explanation:

27 ^(3x) = 81

Replace 27 with 3^3 and 81 with 3^4

3^3^(3x) = 3^4

We know that a^b^c = a^(b*c)

3^(9x) = 3^4

Since the bases are the same, the exponents are the same

9x =4

Divide each side by 9

9x/9 = 4/9

x = 4/9

You might be interested in

Find the surface area of this rectangular prism. Be sure to include the correct unit in your answer.

seropon [69]

I believe that The answer is 8feet

4 0

3 years ago

How does knowing the double 6+6=12 help you solve the near double 6+7=13

forsale [732]

Answer:

6 + 7 = 13

Step-by-step explanation:

We are given the following information in the question:

We know that

$6 + 6 = 12$

We need this information to evaluate

$6+7$

The evaluation can be done with the help of using associative property and distributive property.

Associative property: (a + b) + c = a + (b + c)

The evaluation can be shown as:

$6 + 7\\= 6 + 6 + 1\\=(6 + 6) + 1\\= 12 + 1\\=13$

8 0

3 years ago

◆ Quadratic Equations ◆<br>Please help !

Mila [183]

I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

$\sf ax^2+(1-a(b+c))x+abc-d)$

$\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))$

Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

$\sf x^2+(1-5)x+2$

$\sf x^2-4x+2$

Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

$\sf x\approx\dfrac{4\pm 2.83}{2}$

$\sf x\approx 0.59,3.41$

So the answer would be A.

3 0

3 years ago

Need help worth 34 points!

exis [7]

x + y = 3
- x - x
y = -x + 3

y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
y + 1 = -1(x + 1)
y + 1 = -1(x) - 1(1)
y + 1 = -x - 1
- 1 - 1
y = -x - 2

The answer is B.

6 0

3 years ago

Read 2 more answers

T increased by r the answer

erma4kov [3.2K]

So r is a number that when you add to t it will increase so its

T + r

8 0

3 years ago

Read 2 more answers