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lbvjy [14]
3 years ago
10

27 to the power of 3x=81

Mathematics
1 answer:
hoa [83]3 years ago
8 0

Answer:

x=4/9

Step-by-step explanation:

27 ^(3x) = 81

Replace 27 with 3^3    and 81 with 3^4

3^3^(3x) = 3^4

We know that a^b^c = a^(b*c)

3^(9x) = 3^4

Since the bases are the same, the exponents are the same

9x =4

Divide each side by 9

9x/9 = 4/9

x = 4/9

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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

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\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

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x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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The answer would be:

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I hope this helped! If you have further questions don't be afraid to ask!

~Travis
4 0
3 years ago
Read 2 more answers
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