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PSYCHO15rus [73]
3 years ago
9

Y=3x+3 Fill in the table 3 4 5 6

Mathematics
2 answers:
Allushta [10]3 years ago
4 0

Answer:

Step-by-step explanation:

so if x = 3 4 5 6

then

y=3x3+3

y=12

y=4x3+3

y=15

y=5x3+3

y=18

y=6x3+3

y=21

Andrews [41]3 years ago
3 0
The answer for your question is 3
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-x + 4y = 15<br> 5x + 6y =3 <br> A (3,3)<br> B (-3,-3)<br> C (-3,3)<br> D (3,-3)
viva [34]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
If the length of a rectangle is 2x + 4 and the width is x - 2. write
Bess [88]

Answer:

  P = 6x +4

Step-by-step explanation:

Use the given values in the formula for the perimeter of a rectangle:

  P = 2(L +W)

__

You have ...

  L = 2x +4

  W = x -2

So, the perimeter is ...

  P = 2((2x +4) +(x -2)) = 2(3x +2)

  P = 6x +4

The perimeter of the rectangle is 6x+4.

3 0
2 years ago
Which of the following are in place to limit the government of Balmbak?
sp2606 [1]

Answer:

A limited government is a government thatis established by the people.

determines if a law should be applied.

must act within the law.

has few powers to change the law.

8 0
2 years ago
deirdre is factoring the polynomial x squared plus 2x minus 24. which combination can she use to replace the middle term, 2x ?
Shkiper50 [21]

we are given with

The polynomial x squared plus 2x minus 24

\\\x^2+2x-24\\\\\=x^2+6x-4x-24\\\\\=x(x+6)-4(x+6)\\\\\=(x-4)(x+6)\\

Hence the required combination is 6x and -4x

3 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
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