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Troyanec [42]
3 years ago
10

How to find the equation of a circle

Mathematics
1 answer:
Finger [1]3 years ago
4 0
Hmmm lemme do the first one only

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{5}{ h},\stackrel{3}{ k})\qquad \qquad 
radius=\stackrel{2}{ r}
\\\\\\
(x-5)^2+(y-3)^2=2^2\implies (x-5)^2+(y-3)^2=4
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Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
A study was designed to investigate the effects of two​ variables, (1) A​ student's level of mathematical anxiety and​ (2) teach
Mashcka [7]

Answer:

P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)

And we can find this probability using the complement rule:

P(z>-2)=1-P(z

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(z>-2)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(440,20)  

Where \mu=440 and \sigma=20

We are interested on this probability

P(X>440)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)

And we can find this probability using the complement rule:

P(z>-2)=1-P(z

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(z>-2)=1-P(z

6 0
4 years ago
If (tan^3 theta -1) / (tan theta - 1) - sec^2 theta +1 = 0, find cot theta.
stiv31 [10]
Hey there !

Check the attachment.
Hope it helps you :)

7 0
3 years ago
Read 2 more answers
Help would be nice! Thanks
blsea [12.9K]

Answer:

Number one is 4p+8-9. 8-9= -1 So, 4p-1. Divide both by 4. p=.25

3 0
3 years ago
Read 2 more answers
The football coach is grilling steaks for the team and he likes the grill to be at a temperature of 350 degrees, plus or minus 2
svetoff [14.1K]

Answer:

i think its b. i am not sure sorry

Step-by-step explanation:

3 0
3 years ago
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