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Sauron [17]
3 years ago
7

6th out of 10 questions

Mathematics
1 answer:
Vlad [161]3 years ago
8 0

The answer is D

To solve the answer you would have needed to multiply the reciprocal of \frac{2}{7} but in this case, Unvi multiplied with the reciprocal of 14.

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Find the area of the polygon defined by the coordinates (0,-5),(-5,0),(-15,-20),and(-20,-15)
alekssr [168]

Area of the polygon defined by the given points is 62.5 sq units

Step-by-step explanation:

Step 1 :    

Let P be the point (-5,0)  Q = (0,-5), R = (-15,-20) and S = (20,-15)

We have to to find the area of the polygon PQRS

Step 2 :

The area of polygon given the vertices (x(x_{1} ,y_{1} ), (x_{2} ,y_{2})  ... (x_{n} ,y_{n} ) is given by

Area  = mod ( (x_{1} y_{2}  - y_{1}x_{2}) + (x_{2} y_{3}  - y_{2}x_{3}) + ... (x_{n} y_{1}  - y_{n}x_{1}) ) ÷ 2

Where  x_{n} is the vertex n's x coordinate , y_{n} is the vertex n's y coordinate

Substituting the corresponding values ,

Area of PQRS = mod ( (25 - 0)+ (0-75) +(300-300) +( 0-75)  ) ÷ 2

                       = mod (25-75+0-75) ÷ 2

                       = mod (-125) ÷ 2 = 125 ÷ 2 = 62.5 sq units

Step 3 :    

Answer :

Area of the polygon defined by the given points is 62.5 sq units

4 0
3 years ago
Find the values of x and y using trig
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

The triangle is a right angle triangle. This is because one of its angles is 90 degrees.

Let us determine x

Taking 47 degrees as the reference angle,

x = adjacent side

11 = hypotenuse

Applying trigonometric ratio,

Cos # = adjacent side / hypotenuse

# = 47 degrees

Cos 47 = x/11

x = 11cos47

x = 11 × 0.6820

x = 7.502

Let us determine y

Taking 47 degrees as the reference angle,

y = opposite side

11 = hypotenuse

Applying trigonometric ratio,

Sin # = opposite side / hypotenuse

# = 47 degrees

Sin 47 = y/11

x = 11Sin47

x = 11 × 0.7314

x = 8.0454

7 0
3 years ago
Which fraction is equal to 7
Leya [2.2K]
The answer is E 73/10
3 0
3 years ago
A ferry departs from a port along the Sands River at 10:00 am. The ferry travels at a speed of 15 mph in still water and returns
jek_recluse [69]

Answer:

Speed of river's current = 5 mph

Step-by-step explanation:

Let 'd' be the distance covered  

 Let x be the speed of the rivers current

Speed upstream = 15-x

speed downstream = 15+x

Time = distance / speed

time upstream = \frac{d}{15-x}

time downstream = \frac{d}{15+x}

the ferry trip upstream takes twice as long as its return trip downstream

\frac{d}{15-x}= \frac{2d}{15+x}

divide both sides by d

\frac{1}{15-x}= \frac{2}{15+x}

cross multiply

15+x= 2(15-x)

15+x= 30-2x

Add 2x on both sideds

15+3x= 30

subtract 15 from both sides and divide by 3

3x=15

x=5

Speed of river's current = 5 mph

8 0
3 years ago
Can I get help with these two please?
PSYCHO15rus [73]
Hi, hope this helps :)

3 0
3 years ago
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