Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Pemdas
parnthasees
exponnets
mult or div
add or sub
6x^-2 means
6 times x^-2
rmemeber
x^-m=1/(x^m)
6 times x^-2=6 times 1/(x^2)=6/(x^2)=
Answer: a) y = f(x - 6)
b) y = f(x) - 2
<u>Step-by-step explanation:</u>
For transformations we use the following formula: y = a f(x - h) + k
- a = vertical stretch
- h = horizontal shift (positive = right, negative = left)
- k = vertical stretch (positive = up, negative = down)
a) f(x) has a vertex at (-1, 1)
M has a vertex at (5, 1)
The vertex shifted 6 units to the right → h = +6
Input h = +6 into the equation and disregard "a" and "k" since those didn't change. ⇒ y = f(x - 6)
b) f(x) has a vertex at (-1, 1)
N has a vertex at (-1, -1)
The vertex shifted down 2 units → k = -2
Input k = -2 into the equation and disregard "a" and "h" since those didn't change. ⇒ y = f(x) - 2
Answer:
2003.85
Step-by-step explanation:
I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.
You have save by an increasing amount of 3 pennies per day. You start with 3 and build from that, each day, for 365 days. First, you must figure out what amount of pennies you shoved into your account on the final 365th day.
An= a1+(n-1)d
An=term you want
a1= term you begin with
n= term you want
d= constant amount
A_365= 3 + (365-1)*3
A_365= 1095
Arithmetic Sum: Sn = N/2 (a1 + an)
365/2 * (3 + 1095) = 200385.
This means you've invested a total of 200385 PENNIES after 365 days.
The question asks for dollars, not your rusting lincoln's.
As (I hope) you know, 1 Dollar = 100 pennies
200385 pennies/100 = 2003.85.
This means you have $2003.85 in your account by the conclusion of the 365th day.
