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3 years ago

Determine the domain of the graph

Mathematics

1 answer:

ss7ja [257]3 years ago

7 0

Answer:

The answer is B

Step-by-step explanation:

Graph goes positive infinitily,

but is inclusive of -4 and up.

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<img src="https://tex.z-dn.net/?f=7xy%28x%20-%207%29%20%3D%20%20" id="TexFormula1" title="7xy(x - 7) = " alt="7xy(x - 7) = " a

jeka94

7x^2y-49xy

(7x squared)

8 0

2 years ago

The where sells bagels zero $.75 each the bagel shop sells one dozen for seven dollars which is the better buy

Flura [38]

12 bagels for $.75 is 9 dollars so buying a dozen for 7 dollars is better ☺️

8 0

2 years ago

A zookeeper fills a bucket with f pounds of fish 4 times daily. If he carries 45 pounds

AveGali [126]

This question doesn’t really make sense but 3 of us figured out that the closest option is B 4f=45

4 0

3 years ago

Solve for x in 4x-4/x+4=10

Amiraneli [1.4K]

Answer:

-22/3 =x

Step-by-step explanation:

(4x-4) /(x+4) = 10

Multiply each side by (x+4)

(4x-4) /(x+4) * (x+4) = 10 * (x+4)

(4x-4) = 10 * (x+4)

Distribute

4x-4 = 10x+40

Subtract 4x from each side

4x-4-4x = 10-4x+40

-4 = 6x+40

subtract 40 from each side

-4 -40 = 6x+40-40

-44 = 6x

Divide each side by 6

-44/6 = -6x/6

-22/3 =x

4 0

2 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that $n = 100, p = \frac{81}{100} = 0.81$

Give the value of the standard error for the point estimate.

This is s. So

$s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392$

The value of the standard error for the point estimate is of 0.0392.

7 0

2 years ago