Θ
=
arcsin
(
.7
4.2
)
≈
10
∘
Explanation:
We view the ramp as a right triangle. The hypotenuse is 4.2 and the vertical side .7, which is opposite the angle
θ
we seek.
sin
θ
=
.7
4.2
=
1
6
I'm going to finish the problem but I'll note if we were actually building the ramp we don't need to know the angle; this sine is sufficient.
θ
=
arcsin
(
1
6
)
θ
≈
10
∘
which I think is a pretty steep ramp for a wheelchair.
There will be another inverse sine that is the supplementary angle, around
170
∘
, but we can rule that out as a value for a ramp wedge angle.
Answer: Scaline?
Step-by-step explanation:
Hello :
<span>the nth term of a geometric sequence is :
Un = Up ×r^(n-p) . r is the common ratio
for : p=5 and n= 2
U5 = U2 ×r^3
16 = -2 r^3
r^3 = -8
but : -8 = (-2)^3
so : r = -2
Un = U2 × r^(n-2)
Un = -2 ×(-2)^(n-2)= (-2)^(n-2+1)
</span><span>the nth term of a geometric sequenceis : Un = (-2)^(n-1)</span>
Answer:
What are the options? ban, forbid, prohibit, are some examples
Step-by-step explanation:
