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Illusion [34]
2 years ago
13

Please help answer statistics question? Statistics professor plans classes so carefully that the lengths of her classes are unif

ormally distributed between 50.0 and 52.0 minutes. Find the probability that a given class period runs LESS than 51.5 minutes.
Find the probability of selecting a class that runs less than 51.5 min.

(Type an integer or...; Please show steps HOW to get the answer! Thanks!; This is ONLY one question that I don't get.
Mathematics
1 answer:
alukav5142 [94]2 years ago
4 0
The duration of the class is uniformly distributed with a minimum of 50.0 minutes and a maximum of 52.0 minutes. This means the random variable for class duration X has density function

f_X(x)=\begin{cases}\dfrac1{52.0-50.0}=\dfrac12&\text{for }50.0\le x\le52.0\\[1ex]0&\text{otherwise}\end{cases}

You're looking for the probability that the class runs less than 51.5 minutes, or \mathbb P(X, which is given by the integral

\displaystyle\mathbb P(X
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Answer:

<h2>Reflection.</h2>

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Answer:

V(max) =  8712.07 in³

Dimensions:

x (side of the square base)  = 16.33 in

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Step-by-step explanation:

Let

x  = side of the square base

h = the height of the postal

Then according to problem statement we have:

girth = 4*x     (perimeter of the base)

and

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Then

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Taking dervatives (both menbers of the equation we have:

V´(x)  =  196 x   -  12 x²        ⇒   V´(x) = 0

196x - 12x²  = 0   first root of the equation  x = 0

Then   196 -12x = 0      12x = 196     x = 196/12

x = 16,33 in      ⇒    girth = 4 * (16.33)       ⇒ girth = 65.32 in

and from equation (1)

y = 98 - 4x       ⇒  y = 98 -4 (16,33)

y = 32.67 in

and maximun volume of a carton V is

V(max) = (16,33)²* 32,67

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Answer:

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