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Sliva [168]
2 years ago
14

The bottem half is the answers help pls for big brainnnnnn

Mathematics
2 answers:
SSSSS [86.1K]2 years ago
5 0
Substitute g with 4 and then multiply 4x11, which gives you 44. Then add 5, which gives you 49. C
vlabodo [156]2 years ago
4 0

Answer:

C

Step-by-step explanation:

11 times 4 is 44 plus 5 is 49

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8 0
2 years ago
If this is equal to 8 find x
dolphi86 [110]
I think it is A. not sure though
8 0
3 years ago
Earth's diameter at the equator is 7,926 miles. Find the distance around Earth at its equator to the nearest tenth.
LUCKY_DIMON [66]
If the distance around the earth means circumference, it is, 24,887.64.(not rounded.) C=pi D  (pi=3.14 + d=diameter)
8 0
3 years ago
4.5(8-x)+36=102-2.5(3x+24) show step by step how to solve please.
romanna [79]
Expand

simplify 36 - 4.5x + 36 to -4.5x + 72

simplify 102 - 7.5x - 60 to -7.5x + 42

add 7.5x to both sides

simplify -4.5x + 72 + 7.5x to 3x + 72

subtract 72 from both sides

simplify 42 - 72 to -30

divide both sides by 3

simplify 30/3 to 10

Answer: x = -10
3 0
3 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
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