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3 years ago

Use the formula to factor n8 – 9

Mathematics

1 answer:

gulaghasi [49]3 years ago

3 0

Hi!

The correct answer is ( $n^{4}$ +3)( $n^{4}$ -3)

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Find the value of x What’s the missing angle?

cupoosta [38]

Answer:

x = 15, 72 degrees

Step-by-step explanation:

4x + 12 + 108 = 180

4x + 120 = 180

4x (+ 120 - 120) = 180 - 120

4x = 60

4x/4 = 60/4

x = 15

4x + 12

4(15) + 12

60 + 12

72 degrees

3 0

2 years ago

What best describes the circumference of a circle.?

loris [4]

The length of going from one side of the circle to the (opposite) other side.

7 0

3 years ago

Simplify y^-3 a.3/y b.1/y^3 c.-3y d.-1/y^3

nignag [31]

Answer:

b. $\frac{1}{y^3}$

Step-by-step explanation:

Here we are given $y^{-3}$ and are asked to simplify it. We are going to apply the law of exponents which says that

$a^{-n}=\frac{1}{a^n}$

Hence applying this rule in our problem we get, where a=y and n=3

$y^{-3}=\frac{1}{y^3}$

Hence our C) Option is correct

3 0

3 years ago

Find the quotient of (11 ^ 18)/(11 ^ 3)

astraxan [27]

Answer:

The first choice, $11^{15}$ .

Step-by-step explanation:

The numerator, $11^{18}$ , is equivalent to eighteen " $11$ " multiplied together:

$11^{18} = \underbrace{11 \times 11 \times 11 \times 11 \times \cdots \times 11 \times 11}_{\text{$18$ in total}}$ .

On the other hand, the denominator, $11^{3}$ , is equivalent to three " $11$ " multiplied with one another:

$11^{3} = 11 \times 11 \times 11$ .

Dividing $11^{18}$ by $11^{3}$ would eliminate three " $11$ " from the numerator:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}$ .

In general, dividing an expression by $y^{b}$ ( $y \ne 0$ ) is equivalent to multiplying that expression by $y^{-b}$ .

For example, in this question, dividing $11^{18}$ by $11^{3}$ would be equivalent to multiplying $11^{18}\!$ by $11^{-3}$ . In other words:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & 11^{18} \times 11^{-3} \\ =\; & 11^{18 - 3} \\ =\; & 11^{15}\end{aligned}$ .

6 0

2 years ago

A school snack bar sells a mix of granola and raisins. The mix includes 2 pounds of granola for every 3 pounds of raisins. How m

kifflom [539]

The easiest way to solve a problem like this is to cross multiply and solve

The problem gives us a ratio
2 pounds of granola = 3 pounds of raisins
which makes a ratio of $\frac{2}{3}$
The other ratio is
? pounds of granola = 24 pounds of raisins
which makes a ratio of $\frac{x}{24}$

To solve, set them equal to each other ...
$\frac{2}{3} = \frac{x}{24}$

Now we must cross multiply...
To cross multiply, we multiply 2 and 24
and we multiply 3 and x
Now we have an equation to solve!
3x = 48
To solve and get your final answer, divide...
x = $\frac{48}{3}$

x = 16
You'll need 16 pounds of granola

5 0

3 years ago