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Dmitry [639]
3 years ago
15

Help! Find the measure of the arc or angle indicated.

Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

m<QDC = 77

Step-by-step explanation:

First we need to generate an equation in order to find the value of x.

Thus:

m<QDC = ½(Arc QBC) => Inscribed Angles Theorem)

5x + 17 = ½(4x - 6 + 9x + 4)

5x + 17 = ½(13x - 2)

Multiply both sides by 2

2(5x + 17) = 13x - 2

10x + 34 = 13x - 2

Collect like terms

10x - 13x = -34 - 2

-3x = -36

Divide both sides by -3

-3x/-3 = -36/-3

x = 12

Find m<QDC:

m<QDC = 5x + 17

Plug in the value of x

m<QDC = 5(12) + 17 = 70 + 17

m<QDC = 77

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The two Step equations 5k=20
victus00 [196]

Answer: X = 4

Step-by-step explanation: To solve for k in this equation, we want to get k by itself on the left side of the equation.

Since k is being multiplied by 5, to get k by itself, we need to divide by 5 on the left side of the equation. Since we divided by 5 on the left side, we must also divide by 5 on the right side.

On the left side, notice that the 5's cancel out, so we are simply left with z. On the right side, we have 20 divided by 5 which gives us 4.

Now we have X = 4.

Finally, remember to check your answer by substituting a 4 back into the original equation.

So we have 5 (4) = 20 which is a true statement.

This means that our answer, x = 4 is correct.

5 0
3 years ago
suppose a sample of 1305 tenth graders is drawn. Of the students sampled, 1044 read above the eighth grade level. Using the data
Inessa05 [86]

Answer: (0.771,\ 0.829)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=1305

The proportion of tenth graders read above the eighth grade level. =p=\dfrac{1044}{1305}=0.8

The confidence interval for population proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.8\pm(2.576)\sqrt{\dfrac{0.8(1-0.8)}{1305}}\\\\\approx0.8\pm0.029\\\\=(0.771,\ 0.829)

Hence, the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.771,0.829) .

4 0
3 years ago
What is the width of a rectangle with length 14 cm and area 161 cm^2
Snezhnost [94]
I hope this helps you




Area=width×length



161=width×14


width=161/14


width =11,5
4 0
3 years ago
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AleksandrR [38]
40 square inches
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3 years ago
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These are the numbers 200 50 225 4
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3 years ago
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