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Lilit [14]
2 years ago
15

Find a solution to each equation without writing anything down. 2(x+1)=10

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0

Answer:

4

Step-by-step explanation:

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Sati [7]

Answer:

Step-by-step explanation:

We can find the area by breaking this into two rectangles one 3 by 7 and the other 1 by 2. The area of any rectangle is xy where x and y are its dimensions

A=3(7)+1(2)

A=21+2

A=23 yd^2

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3 years ago
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Sketch one cycle of the cosine function y= cos 2θ
Liula [17]
Based on function transformations, the graph of y= cos(2θ), is the same as the graph of <span>y= cos(θ), with a component B of 2, in which case, it means the period is the only thing that differs

well the period for this function will then be  </span>\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{2}\implies \pi

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7 0
3 years ago
1
galina1969 [7]

Answer:

X .

-1 | 2

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Step-by-step explanation:

7 0
3 years ago
Two adjacent sides of a parallelogram are 6mm and 10mm respectively, and they form an angle measuring 60. Find the area of the p
Snowcat [4.5K]

Answer:

51.96 mm² approximately

Step-by-step explanation:

the first thing you should know is that the area of a rectangle is base*height sin of (

the included angle i.e

Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°

<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>

Aparallelogram= bh sin of sin of the included angle

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately

4 0
3 years ago
Trevor hires a landscaping company m order to seriscape his yard. The company charges $800 per day,
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The answer to this question is B.
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