Alright so lets start with an arbitrary amount of students. Just to help us visualize the problem.
Say, 100 students for the first year when it was founded?
So far,
1996 - 100 students
From 96' to 97', it doubles. So:
1996 - 100 students
1997 - 200 students
From 97' to 98', it doubles AGAIN.
1996 - 100 students
1997 - 200 students
1998 - 400 students
So, what the percentage increase from 100, to 400?
Well, 100 x 4 gives us 400, so it's a 400 percent increase.
The 65 tens blocks can be solved by doing 65x10 which is 650. the 7 ones blocks can be solved by 1x7 which is 7 so you then add up 650 and 7 to get a grand total of 657
By the Pythagorean Theorem:
h^2=x^2+y^2
Which just means that the hypotenuse (longest side) squared is equal to the sum of the side lengths squared...in this case:
h^2=5^2+13^2
h^2=25+169
h^2=194
h=√194
h≈13.93 in (to nearest hundredth of an inch)
Mckensey is correct as shown above.
Cara's mistake was in letting c be a side length instead of the length of the hypotenuse...
Answer:
I think it might be 0.30
Step-by-step explanation:
Answer: GEF = 30 DEF = 40
Step-by-step explanation: By angle summation we know the entire angle
GED = 70, so the smaller angles that make up GED (GEF and DEF) will have to sum up to equal GED. Using this we get:
2x + 10 + 5x - 10 = 70
From here we can combine like terms:
7x = 70
and solve for x
x = 10
Then we can plug the value of x back into the equations given to solve for GEF and DEF
GEF:
2x+10 == 2(10)+10 = 30
DEF:
5x-10 == 5(10)-10 = 40
