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satela [25.4K]
3 years ago
8

2 variable inequalities from their graphs . Please answer. Ty!

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

y≤\frac{1}{3} x+1

Step-by-step explanation:

Since the graph is facing down, We know the equation is y<mx+b

Since slope is rise/run the slope is 1/3.

Since the y intercept (The point where the line hits y) is 1, the equation is

y<1/3x+1

BUT WAIT!

The line is solid meaning that we have to include the line as part of the values. This will make the new equation

y≤\frac{1}{3} x+1

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3 years ago
Find the equation of a straight line passing throught the point listed and having the given gradient. Express your answer in the
Igoryamba
First let's try to find the equation in this form : <span>y = mx + c 

The gradient is given 3 . In a line's equation, x's coefficient represents the line's gradient.

So equation of a line with the gradient of 3, would look like this ;

</span>y= 3x + c
<span>
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We found the line's equation in this form, y= mx + c

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Final answers,

\boxed { y\quad =\quad 3x-1 }

and 

\boxed { -3x+y+1\quad =\quad 0 }

I hope this was clear enough :)




<span>


</span>
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