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3 years ago

A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?

Physics

1 answer:

Maslowich3 years ago

6 0

Answer:

1350N

Explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N

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