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ki77a [65]
2 years ago
6

If you triple the net force on an object, the acceleration will___

Physics
2 answers:
gavmur [86]2 years ago
8 0
The acceleration will triple as well
SOVA2 [1]2 years ago
3 0
F = ma

Assuming that the mass of the object remains constant,
3F = xma
where x is the ratio that the acceleration increases by.

x = 3, so the acceleration will triple.
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4 0
3 years ago
Read 2 more answers
A jet on an aircraft carrier can be launched from rest to 40 m/s in 2 seconds. What is the acceleration of the aircraft? Show st
Alex_Xolod [135]

Answer:

a=20\ m/s^2

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 40 m/s

Time, t = 2 s

We need to find the acceleration of the aircraft. We know that, acceleration is equal to the rate of change of velocity. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{40-0}{2}\\\\=20\ m/s^2

So, the acceleration of the aircraft is 20\ m/s^2.

5 0
2 years ago
A spool whose inner core has a radius of 1.00 cm and whose end caps have a radius of 1.50 cm has a string tightly wound around t
White raven [17]

Answer:

v₁ = 37.5 cm / s

Explanation:

For this exercise we can use that angular and linear velocity are related

        v = w r

in the case of the spool the angular velocity for the whole system is constant,

They indicate the linear velocity v₀ = 25.0 cm / s for a radius of r₀ = 1.00 cm,

         w = v₀ /r₀

for the outside of the spool r₁ = 1.5 cm

         w = v₁ / r₁1

since the angular velocity is the same we set the two expressions equal

        \frac{v_o}{r_o} = \frac{v_1}{r_1}

        v1 = \frac{r_1}{r_o} \ \ v_o

let's calculate

       v₁ = \frac{1.50}{1.00} \ \ 25.0

       v₁ = 37.5 cm / s

4 0
3 years ago
An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?
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Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s
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