Answer:
1.1 percent
Explanation:
C6H5COOH⇌C6H5COO+H
Ka = [C6H5COO-][H+]/[C6H5COOH]
From pKa of 4.2, Ka = 6.3x10^-5
6.3x10^-5 = (x)(x)/0.51-x and assuming x is small...
6.3x10^-5 = x^2/0.51
x^2 = 3.213x10^-5
x =5.67 x10^-3
(5.67x10^-3/0.51)x 100 =1.1 percent
Answer:
I think option A is correct answer
Explanation:
option A
Answer:
D
Explanation:
∆H° = ∆Hf ° (products) – ∆Hf ° (reactants)
Answer:
B
Explanation:
The blubber is so thick acts as installation
Answer:
half-life=T= 36.9 years
Explanation:
As we know that
N
(
t
)
=
N
(
0
)
⋅
0.5
^(t/
T
)
N
(
0
)
=the number of atoms you start with=20 gram
and N
(
t
)= the number of atoms left=0.625 grams
after a certain time=t=184.5 years
T=half life of a nuclide=?
Putting value in above equation we get
half-life=T= 36.9 years
.