The equation is given is of combustion of ethanol.
Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.
The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.
Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.
The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.
To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.
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Since the content of the closed is only hydrogen sulfide (H2S) it is then concluded that the initial pressure will still be equal to the pressure at the equilibrium state. Therefore, the answer to this item is 0.224 atm.
Answer:
0.74 moles of oxygen are required for combustion
Explanation:
Given data:
Number of moles of oxygen required = ?
Mass of Mg = 35.5 g
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 35.5 g/ 24 g/mol
Number of moles = 1.48 mol
Now we will compare the moles of Mg with oxygen.
Mg : O₂
2 : 1
1.48 : 1/2×1.48 = 0.74 mol
0.74 moles of oxygen are required for combustion.
Answer:
Covalent Bond
Explanation:
Because of the unequal sharing of electrons, a covalent bond exists.
Answer:
filtration and Chromatography
Explanation:
The first method used for separation of solids from the mixture is filtration. Filtration is used to separate different solids in a mixture which has particles of different sizes. Other method is Chromatography in which the compounds in the mixtures are separated from each other by moving the mixture at high speed. Due to high speed, the compounds are separated from each other because different compounds have different speeds so it is separated easily.