Amir jogged 10 blocks in 6 minutes at that ratio how long would it take Amir to jog 60 blocks

Given that f(x) is even and g(x) is odd, determine whether each function is even, odd, or neither. (f • g)(x) = ? (g • g)(x) = ?

vekshin1

Answer:

Step-by-step explanation:

If f(x) is even, then f(-x) = f(x).

If g(x) is odd, then g(-x) = -g(x).

(f · g)(x) = f(x) · g(x)

Check:

(f · g)(-x) = f(-x) · g(-x) = f(x) · [-g(x)] = -[f(x) · g(x)] = -(f · g)(x)

(f · g)(-x) = -(f · g)(x) - odd

(g · g)(x) = g(x) · g(x)

Check:

(g · g)(-x) = g(-x) · g(-x) = [-g(x)] · [-g(x)] = g(x) · g(x) = (g · g)(x)

(g · g)(-x) = (g · g)(x) - even

7 0

3 years ago

Read 2 more answers

Answer the Blanks:

vfiekz [6]

Answer:

1. 90°

2. 90°

3. 40°

4. 45°

5. 45°

Step-by-step explanation:

<u>Given:</u> ΔABC,

CD⊥AB,

m∠A=50°,

m∠ACB=85°

<u>Solution:</u>

1. ∠ADC is a right ange, because CD⊥AB, so

$m\angle ADC=90^{\circ}$

2. ∠CDB is a right ange, because CD⊥AB, so

$m\angle CDB=90^{\circ}$

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}$

4. By Angle Addition Postulate,

$m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}$

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

$m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}$

6 0

3 years ago

Rewrite, using the distributive<br> property.<br> 5(2x – 3y) = [?]* - [ ]y

olchik [2.2K]

Answer:

10x-15y

Step-by-step explanation:

So, when they say use the distrubutive property, they basically mean turning this:

a(b+c)

Into this:

ab+ac

So in this case, it would be:

5(2x-3y)

And we will turn it into:

10x-15y

ANother way to think about it is we are multiplying 2x by 5, and -3y by 5. So:

2x*5

=

10x

And

-3y*5

=

-15y

Then we can combine these two:

10x-15y

Hope this helps!

7 0

3 years ago

In a sample of 42 burritos, we found a sample mean 1.4 lb and assumed that sigma equals.5. In a test of the hypothesis H subscri

Sergio [31]

Answer:

D. 0.9953 (Probability of a Type II error), 0.0047 (Power of the test)

Step-by-step explanation:

Let's first remember that a Type II error is to NOT reject H0 when it is false, and the probability of that occurring is known as β. On the other hand, power refers to the probability of rejecting H0 when it is false, so it can be calculated as 1 - β.

To resolve this we are going to use the Z-statistic:

Z = (X¯ - μ0) / (σ/√n)

where μ0 = 1.2

σ = 5

n = 42

As we can see in part A of the attached image, we have the normal distribution curve representation for this test, and because this is a two-tailed test, we split the significance level of α=0.01 evenly into the two tails, 0.005 in each tail, and if we look for the Z critical value for those values in a standard distribution Z table we will find that that value is 2.576.

Now we need to stablish the equation that will telll us for what values of X¯ will we reject H0.

Reject if:

Z ≤ -2.576 Z ≥ 2.576

We know the equation for the Z-statistic, so we can substitute like follows and resolve.

Reject if:

(X¯ - 1.2) / (5/√42) ≤ -2.576 (X¯ - 1.2) / (5/√42) ≥ 2.576

X¯ ≤ -0.79 X¯ ≥ 3.19

We have the information that the true population mean is 1.25, so we now for a fact that H0 is false, so with this we can calculate the probability of a Type II error: P(Do not reject H0 | μ=1.25)

As we can see in part B of the attached image, we can stablish that the type II error will represent the probability of the sample mean (X¯) falling between -0.79 and 3.19 when μ=1.25, and that represents the shaded area. So now we now that we are looking for P(-0.79 < X¯ < 3.19 | μ=1.25).

Because we know the equation of Z, we are going to standardize this as follows:

P ( (-0.79 - 1.25) / (5/√42) < Z < (3.19 - 1.25) / (5/√42) )

This equals to:

P(-2.64 < Z < 2.51)

If we go and look for the area under the curve for Z positive scores in a normal standart table (part C of attached image), we will find that that area is 0.9940, which represents the probability of a Type II error.

Therefore, the power of the test will be 1-0.9940 = 0.006

If we look at the options of answers we have, there is no option that looks like this results, which means there was a probable redaction error, so we are going to stay with the closest option to these values which is option D.

3 0

3 years ago

Anyone who knows how to do this right please

Elan Coil [88]

Answer:

13. 9.77 inches (rounded to 3 s.f.)

14. 249m² (rounded to 3 s.f.)

Step-by-step explanation:

13. To find the arc length, the formula is the angle of the arc out of 360° multiplied by the circumference of the full circle. Circumference of circle: pi × r × 2

$\frac{80}{360}$ × pi × 7 × 2 = 3 $\frac{1}{9}$ pi

= 9.77 inches (rounded to 3 s.f.)

14. To find the sector area, the formula is the angle of the sector out of 360° multiplied by the area of the full circle. Area of circle: pi × r × r

$\frac{285}{360}$ × pi × 10 × 10 = 79 $\frac{1}{6}$ pi

= 249m² (rounded to 3 s.f.)

5 0

2 years ago