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IgorC [24]
3 years ago
8

Find the greatest power of 3 that is divisible of 100!

Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

There is no greatest power of 3 that is divisible of 100.

Step-by-step explanation:

Since any number can always be divisible of 100, there would be no greatest power of 3 that is divisible of 100 since the powers can go on and on forever without stopping, and all powers of 3 is able to be divided by 100.

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I need your help guys please can you answer for me please ​
dybincka [34]
1. In parallelograms, opposite sides are congruent. Therefore EV=16
2. In parallelograms, adjacent angles add up to 180°, so measure of angle V = 100°
3. Opposite angles are equal so measure of angle L = 95°
4. Diagonals of parallelograms bisect each other. DE=10
5. Same rule as #4. LV=18
7 0
2 years ago
I NEED HELP!!!!!!!!!!!!
mart [117]

Answer:

n=7

Step-by-step explanation:

I feel like you need the answer now so i'm not gonna write one.

4 0
3 years ago
How to solve a one step equation of R+3= -6 1/2 <br> please show all the work
IgorC [24]
Solve for R:
R + 3 = -(1/2 + 6)
Put 1/2 + 6 over the common denominator 2. 1/2 + 6 = (2×6)/2 + 1/2:
R + 3 = -(2×6)/2 + 1/2
2×6 = 12:
R + 3 = -(12/2 + 1/2)
12/2 + 1/2 = (12 + 1)/2:
R + 3 = -(12 + 1)/2
12 + 1 = 13:
R + 3 = -13/2
Subtract 3 from both sides:
R + (3 - 3) = -13/2 - 3
3 - 3 = 0:
R = -13/2 - 3
Put -13/2 - 3 over the common denominator 2. -13/2 - 3 = (-13)/2 + (2 (-3))/2:
R = (-13)/2 - (3×2)/2
2 (-3) = -6:
R = (-6)/2 - 13/2
(-13)/2 - 6/2 = (-13 - 6)/2:
R = (-13 - 6)/2
-13 - 6 = -19:
Answer:  R = (-19)/2
6 0
4 years ago
What is the third term in the expansion of (x+2)^3
maw [93]

Answer:

(x+2)^3=x^3-6x^2+12x-8

Step-by-step explanation:

6 0
3 years ago
Guys a little help here!
Ymorist [56]
I think the third one
3 0
3 years ago
Read 2 more answers
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