Let 
. The tangent plane to the surface at (0, 0, 8) is
The gradient is
so the tangent plane's equation is
The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by 
, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation
or 
, 
, and 
.
(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)
The greatest common factor is 2z^3.
In order to find the greatest common factor, always start with the coefficient of the lowest term. Let's see what the factors of 14 are.
Factors of 10: 1, 2, 5, 10
Now we look to see which are also factors of the next highest number.
Factors of 14: 1, 2, 7, 14
Only 1 and 2 are similar factors. Since 2 is also a factor of 70, 2 in the coefficient of our greatest common factor.
Next we look for the term with the least number of z's. 14z^3 is the least number of z's. This means we can take out z^3. Giving us the final answer of 2z^3.
Answer:
Part-To-Whole
Step-by-step explanation:
Part--> 6:18 <--- Whole.
Answer:
No Possible Triangles
Step-by-step explanation:
Deltamath
