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zepelin [54]
3 years ago
6

Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the g

iven equation. (4,-3); y=-5x+8
Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

The slope of the line is m = -5

4 is your x1

-3 is your y1

Plug into the equation y - y1 = m(x - x1)

y + 3 = -5(x - 4)

y + 3 = -5x + 20

   -3             -3

y = -5x + 17

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dolphi86 [110]

Answer:

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3 0
3 years ago
Read 2 more answers
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
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YOUR ANSWER IS A
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4 years ago
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kap26 [50]
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3 years ago
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