Answer:
Base of the original triangle is 12 cm.
Step-by-step explanation:
Let base of triangle be x
two equal legs of triangles by y
therefore perimeter of triangle
x+y+y = 50 or x+2y =50
according to the question
if base is x+3 and leg is y-4
then both are equal
that is x+3 = y-4
y-x = 7 or y =x+7
x+2y =50
x+2(x+7) = 50
x+2x +14 =50
3x +14 =50
3x = 50 -14
3x = 36
x = 12
therefore base of the original triangle is 12 cm
Answer:

Step-by-step explanation:
For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

Or any factor of u but for simplicity let's take the unitary vector.
Then the parametric equations are given by:



Where the point given 
And then since we have everything we can replace like this:




F(x)=x+c, where c is an arbitrary constant.
if c is positive then translation above
if c is negative then translation down
reflection of f(x)=x^2 across x-axis then
f(x)=-x^2
What is the math problem?
The answer would be 40
-4(-2) = 8
8(5) = 40