m∠PQR = 180 - 67
m∠PQR = 113°
m∠PQT is vertical angles with m∠RQS, which means that their measurements are the same
m∠PQT = 67°
hope this helps
OK so we need to find the function v(t) which will tell us where the particle is at any given time.
We know that the derivative of distance is speed and the derivative of speed is acceleration.
In this case we need to work backwords and find the integrals.
a(t) = 13 sin(t) + 4 cos(t)
s(t)= integral of above = 13(-cos(t)) + 4(sin(t)) + C
v(t)= integral of above = -13sin(t) -4cos(t) +Ct + D
Now I believe you have incorrect initial conditions
s(0) = 0, s(2π) = 10
As cos and sin functions have the same value at 0 and 2Pi the above cannot be true.
My guess is that one is s(0) and the other is v(2Pi) or the other way round.
These initial conditions will determine the value of the two constants: C and D.
Hope this helps.
Your Answer Is...
4:00.
Why?
He started at 12:00. Each game took 1 hour and 20 minutes and he played 3 games, so you would add 1:20 to 12:00 3 times, getting 4:00.
≈≈≈≈ Glad I Could Help, And Good Luck! ≈≈≈≈
My Name: AnonymousGiantsFan
Answer:
1. rate = 30, base = 40, percentage = 12
2. rate = 6, base = 24, percentage = 25
3. rate = 16, base = 64, percentage = 25
4. rate = 4, base = 50, percentage = 20
5. rate = 75, base = 80, percentage = 60
Step-by-step explanation:
There are 15 marbles in the bag. This gives us the probability of picking a red marble as 5/15, or 1/3. Because you replace the marble therefore making the probability the same each time, and as it's a logical 'and' operation, you multiply the probabilities like this:
(1/3)•(1/3)=(1/3)^2
Because (a/b)^c = a^c/b^c, P(two red marbles) = 1^2/3^2 = 1/9.
