How many atoms are in 1.204x10^22 moles of arsenic?
1 answer:
Answer:
<h2>0.02 moles </h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
We have the final answer as
<h3>0.02 moles</h3>Hope this helps you
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Answer: The density of the unknown metal is 7.86 g/ml.
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of metal = 25.32 g
Volume of metal = volume of water displaced = (28.22 - 25.00) ml = 3.22 ml
Putting in the values we get:
Thus the density of the unknown metal is 7.86 g/ml
Mass perventage of nitrogen in urea, arginine, ornithine is 46.67%, 32.2%,21% respectively.
What is Mass perventage ?
Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100.
Molecular mass of urea (NH2CONH2) is= 2× (Atomic mass of N ) + 4 × (Atomic mass of H) + (Atomic mass of C) (Atomic mass of O) = 60
Mass percentage of N =
chemical formula for arginine is C6H14N4O2
molar mass of C6H14N4O2=174g/mol
moles of N atoms in C6H14N4O2=4
mass of N atoms=14*4=56g
mass percent of N in C6H14N4O2=(56/174)*100=32.2%
the chemical formula for ornithine is C5H12N2O2
molar mass of C5H12N2O2=132g/mol
moles of N atoms in C5H12N2O2=2
mass of N atoms in C5H12N2O2=2*14=28
mass percent of N in C5H12N2O2=(28/132)*100=21%
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