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joja [24]
3 years ago
5

A 0.100 g sample of a carbon–hydrogen–oxygen compound is combusted in a stream of pure oxygen and produces 0.220 g co2 and 0.239

g h2o. what is the mass percent of hydrogen in the sample?
a.13.3
Chemistry
1 answer:
beks73 [17]3 years ago
8 0

First we assume that the compound containing only C,H,and O is combusted completely in the presence of excess oxygen, so that the only things that can be produced are water and carbon dioxide.

 

From there we should back calculate the amount of Hydrogen that is in the original sample by taking all of the hydrogen in the 0.239g to came from the organic compound.

 

And since we know that the original mass of the sample was .100g, we can also easily get a mass % H by taking the mass Hydrogen calculated over the total original mass (.100 g)

 

So that:

 

0.239g H2O / (18.01 g/mol) = .01327 moles H20

 

.01327 Moles H20 * 2.02g H (per every mole H2O) = .0268g H initially present in the sample

 

.0268g H / .100g sample = 26.8% H by mass

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7 0
3 years ago
Why is carbon monoxide especially dangerous?
mash [69]
Carbon monoxide reacts with hemoglobin of the blood to form carboxyhemoglobin.  The absorption of oxygen worsens, oxygen starvation develops. At a lethal dose, death occurs within 20 days.
4 0
3 years ago
CaBr + KOH – Ca(OH), + KBr (balance first) What mass, in grams, of
neonofarm [45]

Answer:

129.73 g of CaBr₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CaBr₂ + 2KOH –> Ca(OH)₂ + 2KBr

Next, we shall determine the mass of CaBr₂ that reacted and the mass of Ca(OH)₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaBr₂ = 40 + (80×2)

= 40 + 160

= 200 g/mol

Mass of CaBr₂ from the balanced equation = 1 × 200 = 200 g

Molar mass of Ca(OH)₂ = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)₂ from the balanced equation = 1 × 74 = 74 g

SUMMARY :

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Finally, we shall determine the mass of CaBr₂ that react when 48 g of Ca(OH)₂ were produced. This can be obtained as follow:

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Therefore, Xg of CaBr₂ will react to produce 48 g of Ca(OH)₂ i.e

Xg of CaBr₂ = (200 × 48)/74

Xg of CaBr₂ = 129.73 g

Thus, 129.73 g of CaBr₂ were consumed.

6 0
3 years ago
How many moles of Chromium is in 4.41 ×10^24 atoms
zalisa [80]

7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

<h3>How to find the number of moles ?</h3>

Number of moles = \frac{\text{Given number of atoms}}{\text{Avogadro's Number}}

     

<h3>What is Avogadro's Number ?</h3>

Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.

Avogadro's Number = 6.022 × 10²³

Now put the values in above formula we get

Number of moles = \frac{\text{Given number of atoms}}{\text{Avogadro's Number}}

                             = \frac{4.41 \times 10^{24}}{6.022 \times 10^{23}}

                             = 7.32 moles

Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.

Learn more about the Avogadro's Number here: brainly.com/question/1581342

#SPJ1

3 0
2 years ago
If a 12-volt battery produces a current of 20 amps, what is the resistance?
mixas84 [53]

Answer:

0.6 Ω

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Current (I) = 20 A

Resistance (R) =?

From Ohm's law,

V = IR

Where:

V => is the voltage

I => is the current

R => R is the resistance

With the above formula, we can obtain the resistance as follow:

Voltage (V) = 12 V

Current (I) = 20 A

Resistance (R) =?

V = IR

12 = 20 × R

Divide both side by 20

R = 12 / 20

R = 0.6 Ω

Thus the resistance is 0.6 Ω

4 0
3 years ago
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