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lora16 [44]
3 years ago
6

In part 3 of the lab, you discovered the relationship between temperature (T) and volume (V) of a gas.

Chemistry
1 answer:
rewona [7]3 years ago
7 0

\frac{V1}{T1} = k

<u>Explanation:</u>

The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.

This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to the Kelvin temperature

Thus,

\frac{V}{T} = k

where k is a constant

Therefore,

\frac{V1}{T1} = \frac{V2}{T2\\} = \frac{V3}{T3} ...

This shows, as the volume of a gas goes up, the temperature also goes up and vice-versa.

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Answer:

First part: The new volume of the gas is 1786 Liters.

Second part: The temperature required to change the volume of the gas sample is 347 °C

Explanation:

We assume the Charles - Gay Lussac law where, in constant pressure, volume of a gas changes directly proportional to Temperature (in Kelvin)

V1 / T1  = V2/T2

37°C + 273 = 310 K

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1560L / 310°K = V2 / 355K

(1560 / 310) . 355 = V2

1786 L = V2

1560 L / 310 K = 3120 L / T2

T2 = 3120 L . (310 K / 1560 L)

T2 = 620 K

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PLEASEEEE HELP MEEEEE
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Answer:

3.82 x 10²¹ molecules As₂O₃

Explanation:

To find the amount of molecules arsenic (III) oxide (As₂O₃), you need to (1) convert kg to lbs, then (2) convert g As₂O₃ to moles As₂O₃ (via molar mass), and then (3) convert moles to molecules (via Avogadro's number).

1 kilogram = 2.2 lb

Molar Mass (As₂O₃): 2(74.992 g/mol) + 3(15.998 g/mol)

Molar Mass (As₂O₃): 197.978 g/mol

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

0.0146 g As₂O₃            1 kg                  189 lb
------------------------  x  ---------------  x  ------------------  x   ................
         1 kg                     2.2 lb          

       1 mole                6.022 x 10²³ molecules
x  ------------------  x  ---------------------------------------  = 3.82 x 10²¹ molecules As₂O₃
      197.978 g                        1 mole

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