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3 years ago

{y=-3x+20/y=-2x+12} HELP!

Mathematics

1 answer:

olga55 [171]3 years ago

4 0

Answer:

x=20/3 or 6 2/3 or 6.6

Step-by-step explanation:

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I need help with this question I’ll give 15 points

weeeeeb [17]

Answer:

Calculating (5 x 2) violates the order of operations

Step-by-step explanation:

According to the order of operations, multiplies all have equal priority. Therefore, they must be evaluated left to right, not right to left. Evaluating (5 x 2) first is incorrect, and instead (9 x 5) should be calculated first.

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3 years ago

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Use your creativity... Write a short story/problem/question that can be described by the scenario of 4 divided by 1/2

vazorg [7]

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3 years ago

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il63 [147K]

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Step-by-step explanation:

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2 years ago

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Pemdas<br>(-10 + 2²) + 12

schepotkina [342]

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Step-by-step explanation:

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3 years ago

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Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

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3 years ago