2 years ago

Find the values of a and b so that the linear system has the given solution.

Mathematics

1 answer:

mojhsa [17]2 years ago

3 0

Answer:

<em>The values are a=6, b=8</em>

Step-by-step explanation:

The following system of equations

ax - by = 4

bx - ay = 10

Has the solution x=2, y=1. Substituting:

2a - b = 4 [1]

2b - a = 10 [2]

Multiply [1] by 2:

4a - 2b = 8

Add with [2]:

3a = 18

a = 18/3 = 6

a = 6

From [1]:

2*6 - b = 4

b = 12 - 4

b = 8

The values are a=6, b=8

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Write the explicit formula that represents the geometric sequence-2, 8, -32, 128

maks197457 [2]

Well, since we know is a geometric sequence, we can always get the common ratio of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8 -32/8 = -4 <-- our common ratio

the first term is -2

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-2\\
r=-4
\end{cases}\implies a_n=-2(-4)^{n-1}$

4 0

3 years ago

A fraction bar. The top bar is labeled 1. 4 bars underneath the bar are labeled one-fourth. 5 bars underneath the 4 bars are lab

joja [24]

Answer:

Step-by-step explanation:

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