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2 years ago

8

HELP ME PLEASE MATH MATH HELP ASAP ASAP ASAP ASAP ASAP HELP PLEASE PLEASE PLEASE HELP HELP HELP ASAP PLEASE PLEASE PLEASE PLEASE

PLEASE PLEASE PLEASE HELP HELP MATH MATH MATH MATH

2 answers:

Kitty [74]2 years ago

7 0

Answer:D

Step-by-step explanation:

D will go with each funcuation.

Dafna1 [17]2 years ago

6 0

Part D: x= -b/2a

(-1/3, -4/3)

im sorry if this is wrong ;'(

You might be interested in

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

If

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

I need help finding the slope

grin007 [14]

answer:
-1

work:

y = mx+ b

so we can tell that the Y intercept is 1, so we can plug that in. ( + b is the y-intercept)

y = mx + 1

plug in some values to find the slope.
(-1, 2)
2 = -m + 1
- 1 - 1

1 = -1m
/-1 /-1

-1 = m
the slope is -1.

i hope this helps! :D

3 0

3 years ago

Can’t figure this one out either

ELEN [110]

Answer: A

Step-by-step explanation:

<em>- and - = + </em>

-8 (4 - x) = 16

-32 + 8x = 16

8x = 16 + 32

8x = 48

x = 6

7 0

2 years ago

Examine this figure. Which two pieces of information, if true, would help to prove that ΔLMP ≅ ΔNMP by HL? Select two options.

lidiya [134]

Answer:

2. Line MK is the perpendicular bisector of LN.

3. ML ≅ MP

4. ML ≅ MN

Step-by-step explanation:

To prove that ΔLMP ≅ ΔNMP by HL.

The second option or statement states that :

Line MK being the perpendicular bisector of LN then it will explain that angles PML and PMN are right angles. Thus, they are congruent.

Statement 3 and 4 says that

ML, MP, and MN are congruent. Since ML is congruent to MP and MN both. Thus conclude that triangle ΔLMP ≅ ΔNMP by HL

Thus, the correct answer - option 2, 3, and 4.

6 0

2 years ago

Read 2 more answers

Jebb is the tallest player on the basketball team. He is 1 1/2 times as tall as the shortest girls in the sixth grade, who is 4

yanalaym [24]

Answer:

$6\frac{3}{8}$ feet tall.

Step-by-step explanation:

Jebb's Height Calculation:

The heights are given in <em>Mixed Fraction</em>. A mixed fraction is comprised of a whole number and a proper fraction, where as <em>proper fraction </em>is the one whose numerator is less than its denominator and <em>improper fraction </em>is the one whose numerator is greater than its denominator:

Shortest girl in the Sixth Grade = $4\frac{1}{4}$ feet

<em>Converting the height in improper fraction</em>:

$\frac{17}{4}$ feet

Jebb's Height = $1\frac{1}{2}$ feet x The shortest girl height

<em>Converting the height of Jebb in Improper Fraction</em>:

$\frac{3}{2}$ feet x $\frac{17}{4}$ feet

<em>To find the Jebb's height we multiply 3 by 17 and 2 by 4 to get a improper fraction of</em>;

Jebb's Height = $\frac{51}{8}$ feet

We can convert the above in mixed fraction as follows:

$6\frac{3}{8}$ feet tall.

3 0

3 years ago