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zubka84 [21]
2 years ago
11

Helps i sucks at maths pwease help meh

Mathematics
2 answers:
trasher [3.6K]2 years ago
5 0

Answer:

A.

Step-by-step explanation:

Dimas [21]2 years ago
3 0

Answer:

1. D 2. C 3. D 4. A 5. The first 3

Hopes this helps!

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PLEASE HELP?
const2013 [10]

Answer:

When we have a function g(x)

We will have a maximum at x when:

g'(x) = 0

g''(x) < 0.

Now we start with:

g(x) = 3*x^4 - 8*x^3

The first derivation is:

g'(x) = 4*3*x^3 - 3*8*x^2

g'(x) = 12*x^3 - 24*x^2

We can rewrite this as:

g'(x) = x^2*(12*x - 24)

Now we want to solve:

g'(x) = 0 =  x^2*(12*x - 24)

We have one trivial solution, that is when x = 0.

The other solution will be when the term inside of the parentheses is equal to zero.

Then we need to solve:

12*x - 24 = 0

12*x = 24

x = 24/12 = 2

Then g'(x) is equal to zero for x = 0, and x = 2.

Notice that both of these points are included in the interval [ -2,2 ]

Now we need to look at the second derivative of g(x):

g''(x) = 3*12*x^2 - 2*24*x

g''(x) = 36*x^2 - 48*x

Ok, now we need to evaluate this in the two roots we found before:

if x = 0:

g''(0) = 36*0^2 - 48*0 = 0

g''(0) = 0

Then we do not have a maximum at x = 0, this is a point of inflection.

if x = 2:

g''(2) = 36*(2^2) - 48*2 = 48

then:

g''(2) > 0

This is an absolute minimum.

Now let's look only at the interval [ -2,2 ]

We know that:

g''(0) =  0

g''(2) > 0

Then at some point, we should have g''(x) < 0 in our interval.

We need to find the first point such that happens, so let's try with the lower limit of the interval but with the first derivation, if g'(x) < 0, this means that the function is decreasing from that point on, then that point will be a maximum in our interval.

x = -2

g'(-2) = (-2)^2*(12*-2 - 24) = -192

And if we look at the function:

g'(x) = x^2*(12*x - 24)

We can easily see that it is negative unitl x = 0, and then it keeps being negative until x = 2.

So in the interval  [ -2,2 ], the function g'(x) is always negative or zero, this means that in the interval  [ -2,2 ], the function g(x) is always decreasing or constant.

Then the absolute maximum of g(x) in the interval  [ -2,2 ]  will be  x = -2

this means that:

g(-2) ≥ g(x) for all x ∈  [ -2,2 ]

6 0
2 years ago
what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6
BabaBlast [244]
Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-\frac{1}{ \frac{1}{3} }=-3

 so line y=-3x+a
 this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture<span> to test solutions <span>in the application</span></span>


8 0
3 years ago
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The probability is 1/4 or 25%
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3 years ago
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Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one
Colt1911 [192]

Answer:

5

Step-by-step explanation:

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3 years ago
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Arnold is planning on painting a mural. Before painting the mural, Arnold painted the picture on a paper that is 5 inches wide a
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Answer: Mural height: 22ft and the Mural width is 10ft

Step-by-step explanation: I took the test and got it wrong, but they told me the correct answers after I took the test. (I got to K-12) Proof:

5 0
2 years ago
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