The answer is option c.
That is, the wrong step in step 6. It was written that the center of the circunference is the point (2.1). However, the general equation of a circumference is:
(X- (a)) ^ 2 + (Y- (b)) ^ 2 = r ^ 2
Where the point (a, b) is the center of the circle.
So for this case the point for the center is: (-2, -1)
Answer:
T=n-1+4/n
n=(n^2-n+4)/T
Step-by-step explanation:
T=n-1+4/n
n=(n^2-n+4)/T
Answer:
6x^[2]-10
Step-by-step explanation:
Okay this is long:
5x^[2]+4x^[2]+2-7-3x^[2]-5
6x^[2]-10
The probability that a student plays football or baseball is 28/33.
<u>Step-by-step explanation:</u>
From the Venn diagram, it can be determined that
The total number of students = 26+3+9+6+5+7+10 = 66 students.
- The No.of of students play football alone = 26
- The No.of students play baseball alone = 9
- The No.of students play basketball alone = 10
The Probability that a student plays football or baseball = No.of students who knows to play either football or baseball / Total no.of students.
- The No.of students who play both football and baseball = 3
- The No.of students who play both football and basketball = 10
- The No.of students who play both baseball and basketball = 7
- The No.of students play all the games = 5
<u>Now, to find the no.of students who plays football or baseball :</u>
⇒ Total students - (students who plays basket ball alone)
This is because, all the other category students knows to play either football or baseball.
⇒ 66 - 10
⇒ 56 students.
The no.of students who plays football or baseball is 56 students.
Therefore, P(student plays football or baseball) = 56/66 ⇒ 28/33
The Probability is 28/33 which is option D).