Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
There are no values of
m
m
that make the equation true.
No solution
Just divide the input by 4.
f(x) = x/4
Answer:
4-16= -12
16-28= -12
Step-by-step explanation:
frognj;ghgrue;jnvougheruo'gln
X=116 degrees
The relationship between the two angles in the figure are congruent:)