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4 years ago

Second arc (centered at D)

Mathematics

1 answer:

Anna007 [38]4 years ago

6 0

Answer:

The third arc should cross the second arc.

Step-by-step explanation:

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Which fraction is between 2/3 and 6/7

MrRa [10]

Answer:

For example, 16/21

Step-by-step explanation:

Are there choices?

There is an infinite number of numbers between any two numbers.

2/3 = 14/21

6/7 = 18/21

One example of a fraction between 2/3 and 6/7 is 16/21

16/21 is between 2/3 and 6/7.

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2 years ago

What value of s in the equation S/6=18?<br>A.108<br>B.24<br>C.12<br>D.3

Fiesta28 [93]

Answer:

108

Step-by-step explanation:

s=18x6

s=108

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3 years ago

Read 2 more answers

Megan and Kyaa find out they are reading the same book. Although they will be starting on different page numbers,

borishaifa [10]

<h2>40 pages per hour</h2><h2>45 pages per hour</h2><h2> 50 pages per hour</h2><h2>90 pages per hour</h2><h2>125 pages per hour</h2>

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3 years ago

To ride a roller coaster, a visitor must not be less than 60 inches tall.

True [87]

This is saying that your height has to be equal to or greater than 60 inches.

7 0

3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago