Answer:
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Step-by-step explanation:
The total number of different routes that a fire truck can travel the m-distance from F to Z = 4 (Option C).
<h3 /><h3>What is a graph?</h3>
A graph refers to a diagram that shows how a variable varies in relation to one or more other variables, such as a collection of points, lines, line segments, curves, or regions.
Now,
Firstly, refer to the graph attached.
- The graph can be used to manually calculate the number of routes that lead from F to Z.
- F is four m-distances from Z.
- Now, manually calculate the m-distance of the path from F to Z using the 4 boxes that represent it. We discover 6 distinct pathways, each with an m-distance of 4.
Hence, The total number of different routes that a fire truck can travel the m-distance from F to Z = 4 (Option C).
To learn more about graphs, refer to the link: brainly.com/question/4025726
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Answer:


<h3>⎆ <u>In expanded form :-</u></h3>

# ꧁❣ RainbowSalt2²2² ࿐
Hello! :)
<h2>Answer:</h2>
All of the following statements about the cone are true.
2.) The radius is 9 mm.
3.) The base area is calculated using the radius.
4.) The volume is one-third the volume of a cylinder with the same height and diameter.
5.) The volume of the cone is 297 pi millimeters cubed.
<h2>Explanation:</h2>
The radius is always half the diameter, which is why the first choice is false, and the second choice is true.
When calculating the base, you need to use the radius. This means the third choice is true. The formula for the base area is π
Volume of the cone:
V =
π
h
=
× π ×
× 11
= 933.052233 mm²
Volume of a cylinder with the same height and diameter:
V = π
h
= π × 81 × 11
= 891π
= 2799.15669 mm²
2799.15669 ÷ 3 = 933.052233
Option four is true.
297 × π = 933.05223 This is true.
Solution :
2a + 2b = 7 ...1)
4a + 3b = 12 ...2)
In equation, 1)
a = (7 - 2b)/2 ...3)
Putting value of a in equation 2) we get :
4 × (7 - 2b)/2 + 3b = 12
2( 7 - 2b ) + 3b = 12
14 - 4b + 3b = 12
b = 2
Putting value of b in 3) we get :
a = ( 7 - 2×2)/2
a = 3/2 = 1.5
Now,
2x - 3y = 16 ...5)
x + 2y = -6 ...6)
x = -6 - 2y
Putting above value of x in eq 5) , we get :
2( -6 - 2y ) - 3y = 16
-12 - 4y - 3y = 16
7y = -28
y = -4
x = -6 - ( 2× -4 )
x = 2
Hence, this is the required solution.