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Y_Kistochka [10]
4 years ago
10

How do you simply fractions 7m^4?

Mathematics
1 answer:
Yuki888 [10]4 years ago
4 0
Do you have any answer choices? i wanna make sure my answer is correct and is listed :) ? I'll also list it in another comment under this one.
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8 with a exponent of 2 +7
Lyrx [107]

Answer:

71

Step-by-step explanation:

8²=64

64+7=71

I hope this helps!

8 0
3 years ago
Read 2 more answers
CAN SOMEONE EXPLAIN AND MAYBE SHOW ME STEP BY STEP WHY THE ANSWER IS 75degrees. HURRY 50 points and brainiest!!!
Strike441 [17]
<h2>Answer:</h2>

m∠MLQ = 60°. (<u>Equilateral triangle</u>)

Hence, m∠QLP = 30°.

<u>ΔLQP is an isosceles triangle (LQ and LP are congruent)</u>

m∠LPQ = m∠LQP = (180 - 30)/2

m∠LQP = 150/ 2

m∠LQP = 75°.

6 0
3 years ago
15z+35=50 what is the answer to this
Inga [223]

Answer:

z = 1

Step-by-step explanation:

15z + 35 = 50

15z = 50 - 35

15z = 15

z = 15/15

z = 1

7 0
3 years ago
Read 2 more answers
Please help will give brainliest!! thank u
Goshia [24]

9514 1404 393

Answer:

  (c)  162 cm

Step-by-step explanation:

The centroid divides a median into parts with the ratio 1:2, so RL:LD = 1:2. Then RL:RD = 1:(1+2), and RD = 3RL.

  RD = 3·54 cm

  RD = 162 cm

5 0
3 years ago
Which integer is closest to 3V62?
Phoenix [80]

Answer:

\sqrt[3]{62} is closest to 4.

Step-by-step explanation:

Our approach consist in comparing the given cubic root with respect to other two cubic roots consecutive to each other and whose result is an integer. The following condition must be satisfied:

n < \sqrt[3]{62} < n+1

n^{3} < 62 < (n+1)^{3}

If n = 3, then the simultaneous inequation is observed:

3^{3}

27 < 62 < 64

Since 62 is closer to the upper bound, then \sqrt[3]{62} is closest to 4.

3 0
3 years ago
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