Answer:
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
A(0,-2), B(1,1)
Find the slope of AB
m=(1+2)/(1-0)=3
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=3
b=-2 - ----> the point A is the y-intercept
substitute
y=3x-2 - -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
y\geq 3x-2
C(0,2), D(5,1)
step 2
Find the equation of the dashed red line
Let
Find the slope of CD
m=(1-2)/(5-0)=-1/5
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=-1/5
b=2 ----> the point C is the y-intercept
substitute
y=-(1/5)x+2 -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
y<-(1/5)x+2
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Answer:
The equation for the given line is y − 1 = 4(x + 3). Let us convert this equation in slope intercept form y= mx +b, where m is slope and b is the y-intercept. Thus, the slope of this line is 4.Now, we know that the slope of parallel lines are equal. Hence, the slope of the required line is same as the slope of the given line. Hence, the slope of the required line is m = 4It passes through the point (4,32).The point slope form of a line is given by Therefore the equation of the line is y = 4x+16,D is the correct option.
there is 1 number 3 on a 6 sided die
so the probability or rolling a 3 is 1/6
4/24= 1/6
(1/6)*84= 14 had nuts
20/24= 5/6
(5/6)* 84 = 70 no nuts
Given :
A point U located at (1,-4) on the coordinate plane.
To Find :
The reflection of point U on x-axis.
Solution :
Reflection of any point ( h , k ) on x-axis is ( h , - k ) .
So , the reflection of point U i.e ( 1 , -4 ) is ( 1 , 4 ) .
Therefore , the ordered pair describes the location of U' is ( 1 , 4 ).
Hence , this is the required solution .
