What is the equation for slope: 3 and y intercept: -8

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

Answer: 3

Step-by-step explanation: search there :D

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Find the complex zeros of x^3+27. write f in factored form

aliina [53]

$x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0

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4 0

3 years ago

X − (y − y)= for x = 3 and y = 6

dusya [7]

Answer:

Step-by-step explanation:

x − (y − y)

3-(6-6)

3-0

3 0

3 years ago

Read 2 more answers

f(x) = x2. What is g(x)?SIf(x)= x/g(x)(2,1)-5O A.06)-()O B. g(x) = 2x2O C. g(x)-9(x)=(*)O D. g(x)= x2

Andrew [12]

Explanation

As you can see all the possible answers have the same form:

$g(x)=ax^2$

By looking at the picture you'll notice that the graph of g(x) has to pass through the point (2,1). Remember that the points in the graph of g(x) have the form (x,g(x)). Since (2,1) is part of the graph of g(x) then we have the following: