The correct answer is C. <span>f(x)=20(35)x</span>
The given details follow the product rule. The different model of the car available are 756.
Given that:
The different possibility is calculated using the following product rule:
So, we have:
Hence, there are 756 different models available.
Read more about product rules at:
brainly.com/question/3944602
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
=
(
x
2
+
6
)
(
x
+
3
)
Step-by-step explanation:
[Grouping the first 2 terms together and the 2md 2 terms together.]
x
3
+
3
x
2
+
6
x
+
18
=
(
x
3
+
3
x
2
)
+
(
6
x
+
18
)
[Common factor]
=
x
2
(
x
+
3
)
+
6
(
x
+
3
)
{Taking the common bracket]
=
(
x
2
+
6
)
(
x
+
3
)
~Hope this helps! :)
