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ryzh [129]
3 years ago
12

Key X = -X = 1 = -1 Which equation could represent the model?

Mathematics
1 answer:
KiRa [710]3 years ago
4 0

Answer:

hey here the link it.ly/3dXyuz8

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Please help, been stuck on this for ages!
marishachu [46]

Answer:

\boxed {192 cm^{2}}

Step-by-step explanation:

<u>Find the volume of separate cuboids</u> :

<u>Volume (top cuboid)</u> :

⇒ V = 2 x 6 x (10 - 2)

⇒ V = 12 x 8

⇒ V = 96 cm²

<u>Volume (lower cuboid)</u> :

⇒ V = 8 x 6 x 2

⇒ V = 48 x 2

⇒ V = 96 cm²

<u>Volume (prism)</u> :

⇒ 96 + 96

⇒ 192 cm²

8 0
2 years ago
What is the perimeter in units of this rectangle?
Aleks04 [339]
16 units. The long side is 7. And the short sides are 1. 7+1=8. Then you would multiply that by 2. Since each value should represent two sides. You get 16 after that
8 0
4 years ago
Two pipes running together can fill a tank in 20 minutes.
Hunter-Best [27]

Answer:

45, 36

Step-by-step explanation:

let x y minutes be the time for pipes to fill the tank, let n be the water needed to fill the tank.

x-y=9

(n/x)*20+(n/y)*20=n

n is removed by dividing the 2nd equation by n

here u get:

(1/x+1/y)*20=1

you sub x=9+y into the above equation

1/y+1/(9+y)=1/20

((9+y)+(y))*20=(9+y)(y)

180+40y=9y+y2

y2-31y-180=0

then use the quadratic formula and u will find y=36 or -5

-5 is rejected because it is negative

x=36+9=45

therefore it is 36 mins and 45 mins

3 0
3 years ago
The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical
Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{0.8538}

Z = -2.81

Z = -2.81 has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{0.8538}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{1.08}

Z = -2.22

Z = -2.22 has a pvalue of 0.0132

1.32% probability that his average kicks is less than 36 yards

c)

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{1.08}

Z = 2.41

Z = 2.41 has a pvalue of 0.9920

1 - 0.9920 = 0.0080

0.80% probability that his average kicks is more than 41 yards

4 0
3 years ago
Can someone help please?
Katarina [22]

Answer:

g = 6

Step-by-step explanation:

<em>To find the slope you do:</em>

m = change in y ÷ change in x or (y2 - y1) ÷ (x2 - x1)

  • x1 = 4, y1 = -7
  • x2 = g, y2 = -3
  • m (the slope) = 2

<em>Sub in the values:</em>

2 = (-3 - -7) ÷ (g - 4) - we can simplify this

2 = (4) ÷ (g - 4)

4 divided by what gives us 2? 2. This means that g - 4 = 2, g = 2 + 4 which is 6:

g = 6

Hope this helps!

8 0
3 years ago
Read 2 more answers
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