Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
<h3>
Answer: Choice A. Graph (1)</h3>
Reasoning:
If it is at all possible to draw a single vertical line through more than one point on the curve, then the graph is not a function. With graphs (2), (3) and (4), we can draw a vertical line through more than one point on those curves, so they aren't functions. Graph (1) is the only thing left. This graph is a function because it is not possible to draw a single vertical line through more than one point. It passes the vertical line test. Any input (x) leads to exactly one and only one y output.
Nice work on getting the correct answer when you chose "graph (1)".
The frequency stays the same and the wavelength decreases.
Domain: -∞, <span>∞
range: -5,</span><span>∞
(the commas mean through; ex.; -5,</span><span>∞..... that means negative 5 thru infinity)</span>
Answer:
C) x = 1
Step-by-step explanation:
By adding the like terms you get
-12x + 10 = -10x + 8
then you add 12x to both sides and subtract 8 to both sides and get
2 = 2x
which then you would divide 2 by 2 and get 1
